Turunan: Perbedaan antara revisi
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Baris 153:
;Invers
* <math>\frac{d}{dx}(\arcsin x) = \frac{1}{\sqrt{1 - x^2}} = \frac{e^x - e^{-x}}{2}</math>
* <math>\frac{d}{dx}(\arccos x) = \frac{-1}{\sqrt{1 - x^2}} = \frac{e^x + e^{-x}}{2}</math>
* <math>\frac{d}{dx}(\arctan x) = \frac{1}{1 + x^2}</math>
* <math>\frac{d}{dx}(\arccot x) = \frac{-1}{1 + x^2}</math>
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